M,CaCO3=100g/mol
M,MgCO3= 84g/mol
n,amestec =a ,molCaCO3 +b,molMgCO3
m,amestec= 100a,gCaCO3 + 84b.gMgCO3
IN acest amestec exista o masa de C=12a+12b
100a+84b.........................12(a+b)
100..................................13,43
1200a+1200b= 1343a+1128b--> 143a= 72b---> a/b= 72/143