CH3-CH=CH-CH3 + 4[O] ⇒ 2CH3COOH
K2Cr2O7 + 4H2SO4 ⇒ K2SO4 + Cr2(SO4)3 + 4H2O + 3[O]
n butena = 11,2/56 = 0,2 moli
n butena/nK2Cr2O7 = 3/4 nK2Cr2O7 = 4·0,2/3 = 0,8/3 = 4/15 moli
Vs K2Cr2O7 = (4/15) /0,5 = 8/15 l = 0,533 l = 533,33 ml
Vs0K2Cr2O7 + H2SO4) = 538,33 ml