V,H2=28X40-1120 l
m,H2= Vxd= 1120 l x0,089g/l= 99,68g
2mol 2x18g..............2x40g........2g
2Na + 2H2O--------> 2NaOH + H2
x................y....................z.............99,68g
z= 3987gNOH
y= 1794gapa consumata---> m,apa ramasa= 58oo-1794g=.....calculeaza !...
z=99,68molNa
in sistem se gaseste restul de apa si NaOH rezultat
1mol Na.........6,023x10²³atomi(numarul lui Avogadro)
99,68mol............x.................................calculeaza !!!