Ajutati-ma va rog! Scrieti numarul 2017 la puterea 2017 ca o suma de doua patrate perfecte.

Răspuns :

[tex]2017^{2017}=2017\cdot 2017^{2016}=(1936+81)\cdot 2017^{2016}=\\ =1936\cdot 2017^{2016}+81\cdot 2017^{2016}=44^2\cdot (2017^{1008})^2+9^2\cdot (2017^{1008})^2\\ =\boxed{(44\cdot 2017^{1008})^2+(9\cdot 2017^{1008})^2}[/tex]