Daca punctele A B C sunt coliniare astfel incat A apartine (BC) AM=5cm AC=3,4cm M fiind mij seg AB atunci :
AB=?
MC =?
BC=? `


Răspuns :

M-mijl.seg [AB]⇒AM=1/2*AB⇒AB=2*AM⇒AB=2*5cm=10cm
MC=AM+AC
MC=5cm+3,4cm
MC=8,4cm
BC=AB+AC
BC=10cm+3,4cm
BC=13,4cm