a)
[tex] \frac{x + 1}{3} + \frac{1}{2} = \frac{1}{6} \\ 2(x + 1) + 3 = 1 \\ 2x + 2 + 3 = 1 \\ 2x + 5 = 1 \\ 2x = - 4 \\ x = - 2[/tex]
Deci a - 3
b)
[tex]3x = 11 \\ = > x = \frac{11}{3} [/tex]
dar x apartine lui Z => multimea solutiilor este vida
c)
[tex]2(x - 3) + 3(2x - 1) = 5x + 4(x +2 ) \\ 2x - 6 + 6x - 3 = 5x + x + 8 \\ 8x - 3 = 9x + 8 \\ - x = 11 \\ x = - 11[/tex]
c - 1
d)
[tex] |x - 3| = 4 \\ \\ x - 3 = - 4 \\ = > x1 = - 1 \\ \\ x - 3 = 4 \\ = > x2 = 7[/tex]
d- 5
