1)
[tex]\it log_2x = log_264-log_216 \Leftrightarrow log_2x = log_2\dfrac{64}{16} \Leftrightarrow log_2 x= log_2 4\Leftrightarrow x=4[/tex]
4
Efectuăm transformările :
[tex]\it 2lg 3= lg3^2=lg9
\\\;\\
\dfrac{1}{2}lg 9= lg9^{\frac{1}{2}} = lg{\sqrt9} =lg3[/tex]
Ecuația devine:
[tex]\it lgx = lg9+lg6-lg3 \Leftrightarrow lgx = lg \dfrac{9\cdot6}{3} \Leftrightarrow lgx = lg18 \Leftrightarrow x= 18.[/tex]
