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Exercitiul 7 si cu rezolvare(dacă se poate)

   
Descompunem in factori primi numaratorul si numitorul.
Daca gasim cel putin un factor comun si la numarator si la numitor atunci fractia este reductibila, iar daca nu gasim, fractia este ireductibila. 


[tex]\displaystyle \bf\\ a)~~\frac{35}{98} = \frac{5\times 7}{2\times 7^2} = reductibila= \frac{5}{14} \\\\ b)~~ \frac{111}{57} =\frac{3\times 37}{3\times 19} = reductibila= \frac{37}{19} \\\\ c)~~ \frac{33}{91} =\frac{3\times 11}{7\times 13} = ireductibila\\\\ d)~~\frac{202}{360} =\frac{2\times 101}{2^3\times 3^2\times 5} =reductibila= \frac{101}{180} \\\\ e)~~\frac{17}{32} =\frac{17}{2^5} =ireductibila\\\\ f)~~\frac{12}{19} =\frac{2^2\times 3}{19} =ireductibila[/tex]

[tex]\displaystyle \bf\\ g)~~\frac{34}{51}=\frac{2\times 17}{3\times 17}=reductibila=\frac{2}{3}\\\\ h)~~\frac{20}{37}=\frac{2^2\times5}{37}= ireductibila[/tex]