a+b+c=7340q
a-x+b-x+c-x=7340-3x
450+670+(450+670):4=7340-3x
3x=7340-(1120+1120:4)
3x=7340-(1120+280)
3x=7340-1400
3x=5940
x=5940:3
x=1980
a=450+1980
a=2430q cereale in primul siloz ( la inceput)
b=670+1980
b=2650q cereale in al 2-lea siloz (la inceput)
c=280+1980
c=2260q cereale in al 3-lea siloz (la inceput)
verificare
2430q+2650q+2260q=
=5080q+2260q
=7340q in total