Cine imi poate replica vin as afla media geometrica dintre numerele 12 si 3

Răspuns :

[tex] M_{g} = \sqrt{12*3} = \sqrt{36} =6[/tex]


[tex]\it m_g = \sqrt {12\cdot3} =\sqrt{4\cdot3\cdot3} = \sqrt{4\cdot9} =2\cdot3=6 \\\;\\ sau: \\\;\\ m_g = \sqrt {12\cdot3} = \sqrt{36} =6 [/tex]