F.1. Cl, Z= 17 => 17p⁺ si 17e⁻ ; A = 35 , A = Z+N => N= A-Z = 35-17 = 18n⁰
2. Trebuie de senat. 1. leg cov. tripla (≡) , nepolara
3. sarcina nucleara +18 ⇒ 18p⁺ si 18e⁻ ; Z = 18 ; 1s²/2s² 2p⁶/ 3s² 3p⁶
4. a. (X) 1s²/2s² 2p⁶/ 3s² 3p²
b. Ar, Z = 18 , Y = ZAr + 1 = 19 ; 1s²/2s² 2p⁶/ 3s² 3p⁶/4s¹ -1e⁻ ⇒ 1s²/2s² 2p⁶/ 3s² 3p⁶/ (K⁺)
5.pV = nRT => n = pV/RT = 8,2*10/0,082*300 = 3,333 moli Cl2
nr molecule Cl2 = 3,33*NA = 2,00733*10^24
