Salut,
[tex]\left(1-\dfrac{1}2\right)\cdot\left(1-\dfrac{1}3\right)\cdot\left(1-\dfrac{1}4\right)\cdot\ldots\cdot\left(1-\dfrac{1}{49}\right)\cdot\left(1-\dfrac{1}{50}\right)=\\\\\\=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot\ldots\cdot\dfrac{48}{49}\cdot\dfrac{49}{50}=\dfrac{1}{50}.\ A\ fost\ greu\ ?[/tex]
Green eyes.
