f(x)=x la a 2-3x+2 calculati f(0)×f(1)×....f(2015) ajutor va rog

Răspuns :

x^2-3x+2= x^2-2x-x+2= x(x-2)-(x-2) = (x-2)(x-1)
(x-2)(x-1)=0
x-2=0 => x=2
x-1=0 => x=1
Deci  f(0)×f(1)×....f(2015)= f(0) x0x.......xf(2015)= 0