n = V/Vm = 16,8/22,4 = 0,75 moli H2
n = V/Vm = 5,6/22,4 = 0,25 moli N2
m H2 = 0,75×2 = 1,5g
m N2 = 0,25×28 = 7g
m amestec = 1,5+7 = 8,5g
a. fals
b. Maer = 28,9g/mol ---> fals
c. 1 mol H2........2×6,022×10^23 atomi
0,75 moli H2......x = 9,033×10^23 atomi
1mol N2..............2×6,023×10^23 atomi
0,25 moli N2......x = 3,011×10^23 atomi
nr atomi total = 12.044×10^23 atomi
c - fals
d. nr molecule H2 = 0,75×6,022×10^23 = 4,5165×10^23
nr molecule N2 = 0,25×6,022×10^23 = 1,5055×10^23
1,055×3 = 4,5165
d - adevarat
