|2-x|=|x-2|
|x-2|=x-2 pt x>2
x-2=-0,5x+4
1,5x=6
x=6:1.5
x=4>2, solutie buna
verificare
2=-2+4 adevarat
|x-2|=-x+2 pt x<2
-x+2=-0,5x+4
2-4=0,5x
0,5x=-2
x=-4<2, buna
verificare
|-4-2|=2+4 adevarat
buna si aceasta
ramane de verificat x=2
0=-1+4 fals
deci ramane S= {-4;4}