[tex]\displaystyle\\
m(\sphericalangle BOC) = 180 - m(\sphericalangle AOB) = 180 - 70 = 110^o\\\\
\text{Unghiul dintre bisectoare este: }\\\\
\frac{m(\sphericalangle AOB) }{2} +\frac{m(\sphericalangle BOC) }{2} = \frac{70^o }{2} +\frac{110^o }{2} =\frac{70^o +110^o}{2} =\frac{180^o}{2} =90^o
[/tex]
