1 /Radical de oridinul 5 din 128

Răspuns :

Salut,

[tex]\dfrac{1}{\sqrt[5]{128}}=\dfrac{1}{\sqrt[5]{2^7}}=\dfrac{1}{\sqrt[5]{2^2\cdot 2^5}}=\dfrac{1}{2\cdot\sqrt[5]4}=\\\\\\=\dfrac{\sqrt[5]{4^4}}{2\cdot\sqrt[5]4\cdot\sqrt[5]{4^4}}=\dfrac{\sqrt[5]{4^4}}{2\cdot\sqrt[5]{4^5}}=\dfrac{\sqrt[5]{256}}8.[/tex]

Green eyes.