Aflati X si Y din egalitatile :
a)[ 64:(36-x) +10]:2=6
b) [(2Y-4):2-3]-2=14

a) 32:[(36-x)+10]=6
     6[(36-x)+10]=32
218-6x+60=32
6x=246
x=41

b) [2(y-2):2-3]-2=14
      y-2-3-2=14
      y= 14+7
      y=21

a) [64/(36-x)+10]:2=6
Amplicicam 10 cu (36-x)
Obtinem:
{[64+10(36-x)]/(36-x)}:2=6
(64+360-10x)/(36-x)=6x2
(64+360-10x)/(36-x)=12
12(36-x)=64+360-10x
432-12x=424-432
-12x+10x=424-432
-2x=-8 rezulta -8/-2=4


b) (2y-4)/2-3=12
Amplificam 3 cu 2 si obtinem
(2y-4-6)/2=12
2y-4-6=24
2y=24+4+6
2y=34 rezulta ca y=34/2=17!