Ipoteza: trapez dreptunghic ABCD
AB>CD
AB || CD
m(<A) = 90 de grade

[tex]AD=12 \sqrt 3~cm \\ \ \textless \ br /\ \textgreater \ BC= 24~cm \\ \ \textless \ br /\ \textgreater \ AB= 2 \cdot DC[/tex]
Concluzie : AC, DB=?

Perimetrul =?