(x +1)(x-1)(x^2+1)(x^4+1)(x^8+1)...(x^2^100+1)

Răspuns :

(x+1)(x-1)=(x^2-1)
si tot aduni (a-b)(a+b) care e egal cu (a^2-b^2) pana ajungi la
(x^2^100-1)(x^2^100+1)=(x^4^100-1)