fie triunghiul ABC m(A)=90°, AD perpendicular pe BC, D€BC, BC=15cm, AB=12cm, AC=9cm, atunci calculati inaltimea AD

Răspuns :

[tex]AD= \frac{AB*AC}{BC} \\ \\ AD= \frac{12*9}{15} = \frac{108}{15} =7,2 (cm)[/tex]
ialtinea corespunzatoare ipotenuzei= cateta1*cateta2/ipotenuza
AD= AC*AB/BC=12*9/15=12*3/5=36/5=7,2cm
as simple as that!!!
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