(√5-3√2+2 )x(√5+3√2-2) =?

[tex] (\sqrt{5} - 3\sqrt{2} +2)*( \sqrt{5} +3 \sqrt{2} -2) = \sqrt{5} * \sqrt{5} +3 \sqrt{10} -2 \sqrt{5} -3 \sqrt{10}[/tex] -[tex]9 \sqrt{4} + 6 \sqrt{2} +2 \sqrt{5} +6 \sqrt{2} -4=5-18+12 \sqrt{2} - 4=12 \sqrt{2} -17[/tex].=-17 + 16,92 = aproximativ 0 ,08

poza
----------------------------
≈ -17 + 12*1,41 =
-17 + 16,92 =
-0,08=
-8/100=
-2/25
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