stabileste compozitia procentuala a sulfuri de fier


Răspuns :

FeS  sulfura de fier
MFeS= 56+32=88 g/ mol

88g FeS....................56g Fe.....................32gS
100g...........................X................................Y

X=100*56/88= 63,63% Fe

Y= 100*32/88= 36,37%  S