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m(HCl)=365g
w=30% m(sub) =m(sol) x w/ 100%= 365g x30%/100%=109,5g (HCl)
------------------ x 3mol
m(CuO)-? CuO +2 HCl= CuCl2 +H20
1mol 2mol
M(HCl)=36,5g/mol, v=m/M= 109,5/36,5= 3mol
v(CuO)=1mol x 3mol /2mol=1,5 mol
m(CuO)=v(CuO) x M(CuO)= 1,5 mol x 80g/mol=120g
Raspuns: m(CuO)=120g, v(CuO)=1,5 mol