rezolva prin metoda substitutiei urmatorul sistem:y=3x-2 4x+2y=1 va rog cat mai repede

Răspuns :

[tex]\left\{\begin{matrix}
y = 3x - 2\\

4x + 2y = 1\end{matrix}\right.[/tex]

[tex]4x + 2y = 1[/tex]

[tex]4x + 2(3x - 2) = 1[/tex]

[tex]4x + 6x - 4 = 1[/tex]

[tex]4x + 6x = 1 + 4[/tex]

[tex]10x = 5[/tex]

[tex]x = \frac{5}{10} [/tex]

[tex]x = \frac{1}{2} [/tex]

[tex]y = 3x - 2[/tex]

[tex]y = 3 \times \frac{1}{2} - 2[/tex]

[tex]y = \frac{3}{2} - 2[/tex]

[tex]y = \frac{3}{2} - \frac{4}{2} [/tex]

[tex]y = - \frac{1}{2} [/tex]