Suma a 3 numere este 606.Sa se afle numerele stiind ca primul este jumatate din celorlalte doua iar al doilea este o treime din al treilea

a+b+c=606
a=(b+c) :2
b= 1/3×c =c/3
=>a=(c/3+c) :2
(c/3+c) :2+c/3+c=606
4c/3÷2+4c/3=606
4c/3×1/2+4c/3=606
2c/3+4c/3=606
6c/3=606
c=606:6/3
c=606:2/1
c=606×1/2
c=303

b= c/3=303/3=101
a=(b+c) :2= 101+303):2= 404:2=202

[tex]a + b + c = 606[/tex]

[tex]a = \frac{b + c}{2} [/tex]

[tex]b = \frac{c}{3} [/tex]

[tex]a = \frac{ \frac{c}{3} + c }{2} [/tex]

[tex]2a = \frac{c}{3} + c \: | \times 3[/tex]

[tex]6a = c + 3c[/tex]

[tex]6a = 4c[/tex]

[tex]a = \frac{4c}{6} [/tex]

[tex]a = \frac{2c}{3} [/tex]

[tex] \frac{2c}{3} + \frac{c}{3} + c = 606 \: | \times 3[/tex]

[tex]2c + c + 3c = 1818[/tex]

[tex]6c = 1818[/tex]

[tex]c = \frac{1818}{6} [/tex]

[tex]c = 303[/tex]

[tex]a = \frac{2c}{3} [/tex]

[tex]a = \frac{2 \times 303}{3} [/tex]

[tex]a = 2 \times 101[/tex]

[tex]a = 202[/tex]

[tex]b = \frac{c}{3} [/tex]

[tex]b = \frac{303}{3} [/tex]

[tex]b = 101[/tex]