Care este numarul n daca a) 13•2+a•4=248:4 si b)6•4+c•c=88

Răspuns :

a) simplificam prin 2 ca sa reducem calculele. Astfel avem
13+2a=124:4=31
2a=31-13=18
a=9
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b) c^2 = 88-24 = 64
c = rad 64 = +/- 8
a)13×2+a×4=248:4
13×2+a×4=62 |:2
13+2a=31
2a=31-13
2a=18
a=9
S={9}
b)24+c^2=88
c^2=88-24
c^2=64
^ Putere
c1=+√64
c1=8
c2=-√64
c2=-8
S={+-8}