[tex](2x+1)^2 \ \textgreater \ 1\\
|2x+1| \ \textgreater \ 1 \\
i) 2x+1 \ \textgreater \ 1\\
2x \ \textgreater \ 0\\
x\ \textgreater \ 0\\
ii) 2x+1\ \textless \ -1\\
2x \ \textless \ -2\\
x\ \textless \ -1 \\
S:x\in (-\infty ,-1) \cup (0,\infty)[/tex]
