Sistem de ecuații cu metoda reducerii
3x+y=-2
-5x-3y=2
Multumesc

[tex]\left\{\begin{matrix}
3x + y = - 2 \: | \times 3\\

- 5x - 3y = 2\end{matrix}\right.[/tex]

[tex]\left\{\begin{matrix}
9x + 3y = - 6\\

- 5x - 3y = 2\end{matrix}\right.[/tex]

[tex]9x - 5x + 3y - 3y = - 6 + 2[/tex]

[tex]4x = - 4 \: | \div 4[/tex]

[tex]x = - 1[/tex]

[tex]3x + y = - 2[/tex]

[tex]3 \times ( - 1) + y = - 2[/tex]

[tex] - 3 + y = - 2[/tex]

[tex]y = - 2 + 3[/tex]

[tex]y = 1[/tex]

3x+y=-2 |3
-5x-3y=2
urmarim sa reducem termenii in y
9x+3y=-6
-5x-3y=2
4x. / =-4
x=-1

-5x-3y=2
x=-1
5-3y=2
-3y=-3
y=1
verif:
-3+1=-2
5-3=2