[tex]\displaystyle\limit\lim_{x\to 0} \left(\dfrac{\sqrt[5]{x^3-tg^3\ x}}{x}\right)=\displaystyle\limit\lim_{x\to 0} \left(\sqrt[5]{\dfrac{x^3-tg^3\ x}{x^5}}\right)= \displaystyle\limit\lim_{x\to 0}\left(\sqrt[5]{\dfrac{1}{x^2}-\dfrac{tg^3\ x}{x^5}}}\right)\\
\text{Ramane sa calculam ce-i sub radical:}\\
\displaystyle\limit\lim_{x\to 0} \left(\dfrac{1}{x^2}-\dfrac{tg^3\ x}{x^5}}\right)=\displaystyle\limit\lim_{x\to 0} \left(\dfrac{1}{x^2}-\dfrac{\sin^3 x}{\cos^3 x\cdot x^5}\right)=[/tex]
Si de aici ar cam trebui sa te descurci.( eventual aduci la acelasi numitor si aplici L'hopital ,sau cred ca ar merge si prin calcul direct)
