x=cat a parcurs calatorul in trei zile
in prima zi x/4
x-x4=3x/4 cat a ramas dupa prima zi
(3x/4)*25/100=(3x/4)*1/4=3x/16 a parcurs in ziua a doua
3x/4-3x/16=(12x-3x)/16=9x/16 a ramas dupa a doua zi
9x/16=90, 9x=1440, x=160km distanta totala
distanta parcursa a doua zi=3x/16=3*160/16=3*10=30km