cati moli de H3PO4 se gasesc in 294 g H3PO4?
aflati nr de moli din 980 g H3PO4?


Răspuns :

M=3XAH+1XAP+ 4XAO

=3X1+1X31+4X16

=3+31+64

=98g/mol

n=m/M

n1= 294/98

n1=3 moli

n2= 980/98

n2=10 moli

1. MH3PO4 = 3AH + AP + 4AO = 3×1+31+4×16 = 98g/mol

n = m/M = 294/98 = 3 moli H3PO4

2. n = m/M = 980/98 = 10 moli H3PO4