aflati cati litri de apa incap intr-un bazin in forma de paralelipiped dreptunghic cu dimensiunile de: 20cm , 30dm ,10 dm, 2m, 28dm,3m , 0.5dam , 0,12 dam , 0,03 hm

Vparalelipedului dreptunghic=Lxlxh, vom calcula volumurile in dm^{3} deoarece

1dm^{3} =1litru

a) 20cm=2dm, 30dm, 10dm

V=30x10x2=600dm^{3} =600litri

b) 2m=200cm=20dm, 28dm, 3m=300cm=30dm

V=30x28x20=16800dm^{3} =16800litri

c) 0,5dam=5m=500cm=50dm, 0,12dam=1,2m=120cm=12dm, 0,03hm=3m=300cm=30dm

V=50x30x12=18000dm^{3} =18000litri

Obs. 1 dm³ = 1 l, deci voi face toate transformarile in dm

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20 cm=2 dm

V = 30 x 10 x 2 = 600 dm³ = 600 litri

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2 m = 20 dm, 3 m = 30 dm

V = 30 x 28 x 20 = 16800 dm³ = 16800 litri

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0,5 dam = 50dm, 0,12 dam = 12 dm, 0,03 hm = 30 dm

V = 50 x 30 x 12 = 18000 dm³ = 18000litri

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