Inaltimea in piramida patrulatera regulata stiind apotema si latura bazei????Urgent,va rog!!!!!

[tex]\it h^2=a^2_p-a^2_b \\ \\ a_b = \dfrac{\ell}{2},\ \ unde\ \ \ell\ este\ latura\ bazei. [/tex]

Inaltimea piramidei se afla cu teorema lui Pitagora
[tex] h^{2}=a_{p} ^{2}-a_{b} ^{2}[/tex]

unde :
[tex]a_{p}=apotema-piramidei \\ \\ a_{b}=apotema-bazei[/tex]

[tex]a_{p}=apotema-piramidei=a/2[/tex]
unde a = este latura bazei

[tex] h^{2}=a_{p} ^{2}-a_{b} ^{2}=a_{p} ^{2}- (\frac{a}{2})^{2} \\ \\ h= \frac{1}{2} \sqrt{4a_{p} ^{2}- a^{2} } [/tex]