3 intregi si 1 / 2 = ( 3 × 2 + 1 ) / 2 = 7 / 2
1,25 = 125 / 100 = 25/20
a = 3 × ( 7 / 2 - 25 × 2 / 20 ) - ( √5 - 2√5 / 5 ) × √ 5
a = 3 × ( 7 / 2 - 25 / 10 ) - ( 5√5 / 5 - 2√5 / 5 ) × √5
a = 3 × ( 35 / 10 - 25 / 10 ) - (3√5/5 ) × √ 5
a = 3 × 10 / 10 - ( 3 ×√ 25 ) / 5
a = 3 × 1 - 3 × 5 / 5
a = 3 - 3 × 1
a = 3 - 3
a = 0