f(1)=1
f(2)=3
f(3)=5
....
f(2017)=4033
f(2018)=4035
=> s=1+3+5+..+4033+4035
s e progresie aritmetica cu primul termen : 1
si ultimul:4035
suma pt progresia aritmetica e: [(a1+an)•n]/2
a1=primul termen:1
an=ultimul termen:4035
n=nr de termeni
=> s=[(1+4035)•2018]/2=4036•2018/2=4072324