[tex] 6x^{2} -7x-3=0[/tex]
calculam Δ=[tex] b^{2} -4ac[/tex]
unde a=6; b=7; c=3 din ecuatia ta
[tex] 7^{2} - 4*6*(-3)=49+72=121[/tex]
[tex] x_{1} = \frac{-b+ \sqrt{ b^{2} -4ac} }{2a} [/tex]
[tex] x_{1} = \frac{-(-7)+ \sqrt{}121 }{2*6} = \frac{7+11}{12} = \frac{18}{12} = \frac{3}{2} [/tex]
[tex] x_{2} = \frac{-(-7)- \sqrt{(-7)^{2} -4*6*(-3)} }{2*6} = \frac{7- \sqrt{121} }{12} = \frac{7-11}{12} = \frac{-4}{12} = \frac{-1}{3} [/tex]
