2) (a+b+c+d+e) /5 = 1/5
a+b+c+d+e = 5/5 = 1
3) (38+b) :2 = 56
38+b = 56x2= 112
b = 112- 38 = 74
4) (a+a+1+a+2) :3 = 24
3a +3 = 24x3=72
3a = 72-3 = 69
a= 69:3 = 23 ( primul nr)
a+1=23+1=24 ( al 2 lea)
a+2 = 23+2 =25 ( al 3 lea nr)
5) avem :
(a+b+c):3 = 15 ; (a+b):2 = 16 si a=b+2
a+b+c=15x3 = 45
a+b = 2x16 =32
inlocuim : b+2 +b = 32
2b = 32-2 = 30
b = 30:2
b = 15 (al 2 lea nr)
a = b+2 = 15+2
a=17
a+b+c = 45
15+17+c = 45
c = 45-15-17 = 13
c = 13