x2/x1 + x3/x2 + x1/x3=?

x1,x2,x3 Radacinile polinomului X^3+X+1=0


Răspuns :

x³+x-1=0⇔⇔x(x²+1)+1=0⇔(x+1)(x²-1)=0⇔(x+1)(x-1)(x+1)=0⇔(x+1)²(x-1)=0⇔x1/2=-1
            x3=1
X2/x1 + x3/x2 + x1/x3=-1/-1+1/-1+1/-1=1-1-1=-1.
Raspuns:-1
Bafta!