pV=nRT
6X41=nx0,082x300-----> n= 10 mol CxHy
3,6x41= (10 - 232/M)x0,082x300------>232/M= 4 mol scos---> M=58g/mol
1mol................................x,mol
CxHy + (x+y/2)O2---> xCO2 + y/2H2O
4mol.............................n= 4x mol
1mol.................................100g
CO2 + Ca(OH)2----> CaCO3 + H2O
4x........................................1600g
x=4 molC-----> C4Hy
58= 4x12gC+ yx1,gH----> Y= 10------------> C4H10- butan