Aplicand formule (a+b)2=a2+2ab+b2 calculati:
a) (x+4)la a 2;
b)(x-3)la a 2



Răspuns :


[tex](x + 4) {}^{2} = x {}^{2} + 2 \times x \times 4 + 4 {}^{2} [/tex]
[tex] = x {}^{2} + 6x + 16[/tex]
[tex](x - 3) {}^{2} = x {}^{2} - 2 \times x \times 3 + 3 {}^{2} [/tex]
[tex] = x {}^{2} - 6x - 9[/tex]
a) ( x + 4)² =  x² + 8 x + 16 

b)  ( x - 3)² = x² - 6 x + 9