[tex] Calculezi~DELTA~= (6-i)^2 -4(5-i)=36-1-12i-20+4i=15-8i=(4-i)^2\\ \\ radacina_{1}=\frac{(6-i)-\sqrt{(4-i)^2}}{2}=\frac{6-i-4+i}{2}=1\\ \\ radacina_{2}= \frac{(6-i)+\sqrt{(4-i)^2}}{2}=\frac{6-i+4-i}{2}=\frac{10-2i}{2}=5-i\\ \\ Suma~ceruta~este~1+\sqrt{5^2+1^2}=1+\sqrt{26} .\\ \\ Raspuns~corect~F. [/tex]
