comparati 4 la puterea 12 si 8 la puterea 9. va rog

Răspuns :

[tex] 4^{12}=(2^{2})^{12}=2^{2\cdot12}=2^{24} [/tex]


[tex] 8^{9}=(2^{3})^{9}=2^{3\cdot9}=2^{27} [/tex]


[tex] 4^{12}<8^{9} [/tex]



4=2^2

4¹²=(2²)¹²=2²×¹²=2²⁴

8=2^3

[tex] {8}^{9} = ( {2}^{3} ) {}^{9} = {2}^{3} \times 9 = {2}^{27} [/tex]

[tex] {4}^{12} = {2}^{24} \\ {8}^{9} = {2}^{27} [/tex]

Răspuns :
[tex] {4}^{12} < {8}^{9} [/tex]