2. c) 3x<=9 , x<=3 => x€(-infinit, 3] => solutia in multimea nr nat este pt x=1,2,3
3. a) 2-2x+y-y+2x = 2
b) [x+(1/2)]^2 daca il descompunem va da ce e in exercitiu.
c) (3√2-√10x)/-√2=(√10x-3√2)/√2
Rationalizam si facem calcule
(√20x-6)/2=(2√5x-6)/2=[2(√5x-3)]/2=√5x-3
Daca vrei poti scoate x si va da x=(3√5)/5
