Arata ca 3*2^10+3*2^11=pp

Răspuns :

3*2^10+3*2^11=

3×2^10 × ( 1 + 2) =

3 × 2^10 ×3 =

3^2 × (2^5)^2 = > patrat perfect

3*[tex] 2^{10} [/tex]+3*[tex] 2^{11} [/tex]=

3*[tex] 2^{10} [/tex](1+2)=3*[tex] 2^{10} [/tex]*3=[tex] 3^{2} [/tex]*[tex] (2^{5})^{2} [/tex]=pp