Va rog repede.Dau multumesc.Sa fie corect va rog.

2x-1=<5
2x=<6
x=<3
A={0,1,2,3}

K<3
K={0,1,2}
X=2^(k+1)
X={2¹,2²,2³}
B={2,4,8}

A reunit cu B={0,1,2,3,4,8}
A intersectat cu B={2}
A-B={0,1}
B-A={4,8}

A = { x ∈ N l 2 x - 1 ≤ 5 }

B = { x ∈ N* l x= 2^(k + 1) ; k < 3 }

2 x - 1 ≤ 5

2 x ≤ 5 + 1

2 x ≤ 6 ⇒ x ≤ 6 : 2 ⇒ x ≤ 3 ⇒ A = { 0, 1, 2, 3 }

k < 3 ; ⇒ k =0, 1, 2

x = 2

x = 2 ⁽ ¹ ⁺ ¹ ⁾ = 2 ² = 4

x = 2 ⁽ ² ⁺ ¹ ⁾ = 2 ³ = 8

B = { 2; 4; 8 }

A ∪ B = {0, 1, 2, 3, 4, 8 }

A ∩ B = {2}

A - B = { 0, 1; 2; 3 } - {2; 4; 8 } = { 0; 1; 3 }

B - A = { 4; 8 } → elementele ce apartin multimii B, dar nu apartin lui A