aflati perechile de numere intregi (xy) pentru care (2x-1)(y+3)=6

(2x-1)(y+3)=6 =1*6=2*3=3*2=6*1=

(-1)*(-6)=(-2)*(-3)=(-3)*(-2)=(-6)*(-1)

2x-1=1..x=1 y+3=6...y=3

2x-1=2..x=3/2∉Zfar solutie

2x-1=3,,,x=2 y+3=2...y=-1

2x-1=6...far solutie in Z

2x-1=-1...x=0...y+3=-6...y=-9

2x-1=-2 far solutie in Z

2x-1=-3...x=-1...y+3=-2...y=-5

2x-1=-6 fara solutie in Z

(x;y) ∈{(1;3);(2;-1);(0;-9);(-1;-5)}