12 descompus=2 radical din 3 .Cum ajung de la forma descompuna la numarul care a fost descompus?

[tex] \sqrt{12} =\sqrt{4*3} =\sqrt{2^2*3} =2\sqrt{3} [/tex]

[tex] 1) \\ \\ \sqrt{12} = \sqrt{2 \times 2 \times 3} = \sqrt{(2 \times 2 \times 3)} = \sqrt{ {2}^{2} \times 3 } = 2 \sqrt{3} \\ \\2) \\ \\ \sqrt{12}= \sqrt{(4 \times 3)} \\ \\ \sqrt{(4 \times 3)}= \sqrt{4} \times \sqrt{3} \\ \\ \sqrt{4} \times \sqrt{3}=2 \sqrt{3} [/tex]