1) a b + a c = 20 si b + c = 5
ab + ac = 20
a ( b + c ) = 20 → am dat factor comun pe a
a × 5 = 20
a = 20 : 5
a = 4
a³ × ( b + c ) = 4³ × 5 = 64 × 5 = 320
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2) a² - ab + ac = - 15 si a = 5
5² - a ( b - c ) = - 15
25 - 5 × ( b - c ) = - 15
5 × ( b - c ) = - 15 - 25 = - 40
b - c = ( - 40) : 5
b - c = - 8
( b - c ) ² = ( - 8 ) ² = 64