a = primul numar = descazut
b = al 2-lea numar = scazator
a - b = a : 3 |×3
3×a - 3×b = a
3×a - a = 3×b
2×a = 3×b ; a + b = 50
a |-------|-------|-------|
b |-------|-------|
3 + 2 = 5 segmente egale = 50
1 segment egal = 50 : 5 = 10
a = 3 × 10 = 30 (primul numar)
b = 2 × 10 = 20 (al 2-lea numar)
V.
30 + 20 = 50
30 - 20 = 30 : 3
10 = 10 (adevarat)